a = 1
b = 1
c = 1

def is_pythag(a, b, c):
    return a < b < c and a**2 + b**2 == c**2


for a in range(1, 1000):
    for b in range(1, 1000):
        for c in range(1, 1000):

            if c % 100 == 0:
                print(f"iter {a} {b} {c}", end="\r")




            if is_pythag(a, b, c) and a+b+c==1000:
                print(f"a {a} b {b} c {c}")
            else:
                continue