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challenges/5/main.py

22 lines
358 B

num = 2520
factors = [i for i in range(1, 20+1)]
def perf_num(num):
for f in factors:
if num % f == 0:
pass
else:
return False
else:
return True
i = 1
while True:
if i % 1000 == 0:
print("status", i, end='\r')
if perf_num(i):
print("found num", i)
break
i += 1